(3x-2)^2-9x^2=4(1-3x)

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Solution for (3x-2)^2-9x^2=4(1-3x) equation: 



(3x-2)^2-9x^2=4(1-3x)

We move all terms to the left:

(3x-2)^2-9x^2-(4(1-3x))=0

We add all the numbers together, and all the variables

-9x^2+(3x-2)^2-(4(-3x+1))=0



We calculate terms in parentheses: -(4(-3x+1)), so:

4(-3x+1)

We multiply parentheses

-12x+4

Back to the equation:

-(-12x+4)



We get rid of parentheses

-9x^2+(3x-2)^2+12x-4=0

We add all the numbers together, and all the variables

-9x^2+12x+(3x-2)^2-4=0

We move all terms containing x to the left, all other terms to the right

-9x^2+12x+(3x-2)^2=4

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